(0.5x^2)+144=225

Solution for (0.5x^2)+144=225 equation:

(0.5x^2)+144=225

We move all terms to the left:

(0.5x^2)+144-(225)=0

We add all the numbers together, and all the variables

(0.5x^2)-81=0

We get rid of parentheses

0.5x^2-81=0

a = 0.5; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·0.5·(-81)
Δ = 162
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{162}=\sqrt{81*2}=\sqrt{81}*\sqrt{2}=9\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-9\sqrt{2}}{2*0.5}=\frac{0-9\sqrt{2}}{1}
=-\frac{9\sqrt{2}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+9\sqrt{2}}{2*0.5}=\frac{0+9\sqrt{2}}{1}
=\frac{9\sqrt{2}}{1}
$